Cannot find file path startfile python
WebYou cannot use an absolute path, unless your terminal is in that directory. Hence, you can do as in the following: import os def rename(directory): os.chdir(directory) # Changing to … WebJan 16, 2013 · If this is a Python 3 & unicode problem, I suggest trying to fix the string first: path = "\\\\myshare\folder" path = bytes (path, "utf-8").decode ("unicode_escape") print …
Cannot find file path startfile python
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WebOct 29, 2024 · os.startfile require file directory + file name (if your script not in the same directory with the files) import random import os himg = 'C:\\Users\\Vl\\Desktop\\aaaa\\himg\\' files = os.listdir (himg) d = random.choice (files) rng1 = (random.randint (0, 10)) if (rng1 % 2) == 0: os.startfile (himg + d) Share Improve this … WebFeb 22, 2024 · I am trying to select a random music file from a folder in Python using the windows commands: random.choice () os.listdir () os.startfile () Here is the code: import …
WebJul 3, 2016 · If you start the Python script from another directory, e.g. in a command prompt or the run dialog, then the working directory won't be the Python script directory, and startfile will fail. The VBS script also inherits this working directory. WebJul 28, 2011 · There is no option to wait for the application to close, and no way to retrieve the application’s exit status. If you know the path of the application to open the file with, …
WebSep 9, 2008 · It should be from path import Path then Path ('mydir/myfile.txt').abspath () – Frak Jun 5, 2024 at 14:51 1 There are no typos, you may have been using a different path module. The linked module uses a class named path. WebTo fix this, change the loop in your code to: for root, dirs, filenames in os.walk (folder): for filename in filenames: filename = os.path.join (root, filename) ... process file here. which …
WebJan 30, 2024 · In python, we use the method os.startfile () to start or open the file. To use this method, we pass a parameter to the method in string data type, which shows a valid …
WebMar 7, 2024 · file = r'c/:folder/file.txt' os.startfile (file) returns FileNotFoundError: [WinError 2] The system cannot find the file specified: 'c:/folder/file.txt' I have also tried to check if … list of italian americansWebOct 14, 2024 · import os file_name = raw_input("File Name: ") #file to be searched #cur_dir = raw_input("Search Directory: ") # Dir from where search starts can be replaced with … imbir catering wicieWebFeb 22, 2024 · You can use glob.glob() to find files using wildcard instead of listing all the files and then go through the file list to find the required files. Also there is no xdg-open in Windows platform, use os.startfile() instead of subprocess.call(). imbisbude theesenWebOct 11, 2024 · Description What steps will reproduce the problem? 'conda create -n myenv spyder-kernels' in miniconda cmd 2)change default env in prefrences 3)restart console Traceback ERROR:traitlets:Failed to r... list of i survived books in orderWebFeb 26, 2024 · #!/usr/bin/python # -*- coding: utf-8 -*- import os import enum from os import path, startfile # Enum for size units class SIZE_UNIT (enum.Enum): BYTES = 1 KB = 2 MB = 3 GB = 4 def convert_unit (size_in_bytes, unit): """ Convert the size from bytes to other units like KB, MB or GB""" if unit == SIZE_UNIT.KB: return size_in_bytes/1024 elif unit … imbi overseas restaurantWebOct 30, 2013 · There are lots of alternatives to fix this, starting with doubling the backslash: os.path.join is the safest and most portable choice. As long as you have "c:" hardcoded … list of italian cheesesWebApr 10, 2015 · Use GetShortPathName from kernel32.dll and access the file in this way. That is nice, but I cannot use it, since I need to use the paths in a way shutil.rmtree … list of italian chefs